40x^2-70x+26=14-9x^2-10

Solution for 40x^2-70x+26=14-9x^2-10 equation:

40x^2-70x+26=14-9x^2-10

We move all terms to the left:

40x^2-70x+26-(14-9x^2-10)=0

We get rid of parentheses

40x^2+9x^2-70x-14+10+26=0

We add all the numbers together, and all the variables

49x^2-70x+22=0

a = 49; b = -70; c = +22;
Δ = b2-4ac
Δ = -702-4·49·22
Δ = 588
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{588}=\sqrt{196*3}=\sqrt{196}*\sqrt{3}=14\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-14\sqrt{3}}{2*49}=\frac{70-14\sqrt{3}}{98}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+14\sqrt{3}}{2*49}=\frac{70+14\sqrt{3}}{98}
$